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0.5x^2+8x-3840=0
a = 0.5; b = 8; c = -3840;
Δ = b2-4ac
Δ = 82-4·0.5·(-3840)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*0.5}=\frac{-96}{1} =-96 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*0.5}=\frac{80}{1} =80 $
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